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3 years ago

Find the smallest square number that is divisible by each of the numbers 8, 9 and 10

Mathematics

2 answers:

Vsevolod [243]3 years ago

8 0

Answer:

Step-by-step explanation:

Find Least common denominator of 8, 9 & 10

8 = 2 * 2 * 2

9 = 3* 3

10 = 5*2

LCM = 2*2*2*3*3*5 = 8 * 9 * 5 = 360

To make 360 a perfect square,multiply by 10

360*10 = 3600 is a perfect square

vekshin13 years ago

7 0

Answer:

Step-by-step explanation:

Find the LCM of 8,9 and 10.

Prime Factorization to find LCM,

8 = 2 × 2 × 2

9 = 3 × 3

10 = 2 × 5

LCM ( 8 , 9 , 10 ) = 2 × 2 × 2 × 3 × 3 × 5 =360

But 360 is not square

Now we make the pairs complete by multiplying same numbers in prime factorization of LCM.

We need one 2 and one 5 to complete the pair.

We get, Least Square number = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 3600

Hope this helps

good Luck

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Andreas93 [3]

If you subtract 2 from both sides

It would be 4=-4x

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3 years ago

Type the correct answer for each.

xxTIMURxx [149]

If point $\left(x,\ \frac{\sqrt{7}}{3}\right)$ is on the unit ircle, then:

$x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\ \\ \Rightarrow x^2+ \frac{7}{9} =1 \\ \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9} \\ \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}$

Since, the point is in the second quadrant, x is negative.

Thus, $(x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)$

Part A:

$3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\ \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\ \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\ \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta$

Therefore, $-6\tan\theta=3\sqrt{7}$ .

Part B:

$- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x} \\ \\ =\tan\theta$

Therefore, $\tan\theta=- \frac{ \sqrt{7} }{2}$

8 0

3 years ago

3x+ 2y= 4 solving for x

Jet001 [13]

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$3x + 2y = 4$

$3x = -2y + 4$

Now divide both sides by 3.

$x = \dfrac{-2y + 4}{3}$

4 0

3 years ago

Read 2 more answers

Give the domain and range of the relation.

Alex_Xolod [135]

Answer:

Please check the explanation.

Step-by-step explanation:

Finding Domain:

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

From the given graph, it is clear that the starting x-value of the line is x=-2, the closed circle at the starting value of x= -2 means the x-value x=-2 is included.

And the line ends at the x-value x=1 with a closed circle, meaning the ending value of x=1 is also included.

Thus, the domain is:

D: {-2, -1, 0, 1} or D: −2 ≤ x ≤ 1

Finding Range:

We also know that the range of a function is the set of values of the dependent variable for which a function is defined

From the given graph, it is clear that the starting y-value of the line is y=0, the closed circle at the starting value of y = 0 means the y-value y=0 is included.

And the line ends at the y-value y=2 with a closed circle, meaning the ending value of y=2 is also included.

Thus, the range is:

R: {0, 1, 2} or R: 0 ≤ y ≤ 2

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3 years ago

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ValentinkaMS [17]

Answer:

the answer is 175

Step-by-step explanation:

you will do 2500*7/100

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3 years ago