In the graph above, the coordinates of the vertices of / are T(4, 4), U(2, –2), and V(6, –2). If / is reflected across the y-axi
2 answers:
Answer:
Step-by-step explanation:
We know that the coordinates of a point A(x,y) after the reflection across y-axis becomes :-
i.e. the polarity of x-coordinate changes but the y-coordinate remains exactly same.
Now, point U(2, -2) undergoes reflection across y-axis , then its image will be :-
Thus , we get the coordinates of U' =(-2,-2)
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For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:
g(f(x)) = x = f(g(x))
<u>The restriction is:</u>
x ≠ 4
<u>The inverse is:</u>
Here our function is:
We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.
(x - 4)^2 = 0
x - 4 = 0
x = 4
So the only value of x that we need to remove from the domain is x = 4.
To find the inverse we try with the general form:
Evaluating this in our function we get:
Remember that the thing above must be equal to x, so we get:
From the two above equations we find:
b = 11
a = 4
Thus the inverse equation is:
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