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VladimirAG [237]
3 years ago
12

Jenny packaged 108 eggs in 9 cartons. write this statement as a rate ​

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Jenny packaged 12 eggs per carton

Step-by-step explanation:

we know that

To find the rate divide the total amount of eggs by the total number of cartons

so

\frac{108}{9}=12\frac{eggs}{carton}

therefore

The statement is

Jenny packaged 12 eggs per carton

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Rob peeled 125 oranges in 5 hours. At that rate, how many oranges<br> would he peel in 12 minutes?
marin [14]

Answer:

\boxed {\tt 5 \ oranges}

Step-by-step explanation:

Let's set up a proportion.

\frac{oranges}{minutes} =\frac{oranges}{minutes}

He can peel 125 oranges in 5 hours. First, let's find the minutes in 5 hours.

There are 60 minutes in 1 hour, so multiply 60 and 5 (60*5=300). There are 300 minutes in 5 hours.

\frac{125 \ oranges}{300 \ minutes}=\frac{oranges}{minutes}

We don't know how many oranges he can peel in 12 minutes. So we say he can peel x oranges in 12 minutes.

\frac{125 \ oranges}{300 \ minutes}=\frac{x \ oranges}{12 \ minutes}

\frac{125 \ }{300 \ }=\frac{x \ }{12 }

Solve for x by isolating it. x is being divided by 12. The inverse of division is multiplication. Multiply both sides of the proportion by 12.

12*\frac{125 \ }{300 \ }=\frac{x \ }{12 \ }*12

12*\frac{125 \ }{300 \ }=x

12*0.416666667=x

5=x

Rob can peel 5 oranges in 12 minutes.

6 0
4 years ago
Read 2 more answers
10^3 I need some help can someone help please.
Taya2010 [7]

Answer:

1,000

Step-by-step explanation:

10³ is the same as saying 10×10×10

This is equal to 1,000

Hope that helps!

5 0
2 years ago
Read 2 more answers
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
What is the slope-intercept form of the equation of the line with the slope of -5/8 that passes through the point (-14,6)
inessss [21]

Step-by-step explanation:

y-y1 = m(x-x1) is the equation for a linear line in y=mx+b (slope intercept)

slope = m = -5/8

x1 = -14

y1 = 6

y-6 = -5/8 (x--14)

y-6 = -5/8 (x+14)

y-6 = -5/8x-70/8

y-48/8= -5/8x-70/8

y = -5/8x - 22/8

When x = 0, y = -22/8, which makes (0, -22/8) your y intercept

5 0
3 years ago
What’s the correct name for that line?
eimsori [14]

GM, because when naming a line, you go from left to right just like how we read.

8 0
4 years ago
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