The average rate of change of a function, g(x), over an interval [a, b] is given by
Thus, the average rate of change of
over the interval
is given by:
![Average\ rate\ of\ change= \frac{[-(8)^2-4(8)]-[-(6)^2-4(6)]}{8-6} \\ \\ = \frac{(-64-32)-(-36-24)}{2} = \frac{-96-(-60)}{2} = \frac{-96+60}{2} = \frac{-36}{2} \\ \\ -18](https://tex.z-dn.net/?f=Average%5C%20rate%5C%20of%5C%20change%3D%20%5Cfrac%7B%5B-%288%29%5E2-4%288%29%5D-%5B-%286%29%5E2-4%286%29%5D%7D%7B8-6%7D%20%5C%5C%20%20%5C%5C%20%3D%20%5Cfrac%7B%28-64-32%29-%28-36-24%29%7D%7B2%7D%20%3D%20%5Cfrac%7B-96-%28-60%29%7D%7B2%7D%20%3D%20%5Cfrac%7B-96%2B60%7D%7B2%7D%20%3D%20%5Cfrac%7B-36%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20-18)
Answer:
Step-by-step explanation:
for number 21 it is tulsa
for number 22 it is tornado
and idk the last one
Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
How to do it
3n=25.50
c= 8.5t
The answer is D. He divided both sides by 5 instead of dividing both sides by -5.
