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lara31 [8.8K]
3 years ago
10

The zeros for f(x)=x^4-4x^3-9x^2+36x are

Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0
X^4 - 4x^3 - 9x^2 + 36x = 0
 x(x^3 - 4x^2 - 9x + 36) = 0
x(x^2(x - 4) - 9(x - 4) = 0
x(x + 3)(x - 3)(x - 4) = 0

the zeroes are  -3, 0, 3, 4  Answer
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Answer:

Step-by-step explanation:

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You have 480 grams of a radioactive kind of samarium. If its half-life is 90 years,
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Answer:

120 grams will be left after 180 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

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where,

N(t) = quantity of the substance remaining

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From the information given we know that:

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And we want to find how much will be left. For this we use the above formula.

N(t)=480\left(\frac{1}{2}\right)^{\frac{180}{90}}\\\\N(t)=480\left(\frac{1}{2}\right)^2\\\\N(t)=480\cdot \frac{1}{2^2}=120

120 grams will be left after 180 years.

3 0
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What’s the answer of this problem
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D) 15

Step-by-step explanation:

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We substitute into the formula to get:

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Answer:

31.4 in

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