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Anon25 [30]
3 years ago
6

There are 5 white balls, 8 red balls, 7 yellow balls and 4 green balls in a container. A ball is chosen at random.

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

green=4/24    yellow=7/24     black=0/24    red, yellow=15/24

Step-by-step explanation:

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Please help me with this answer
ra1l [238]

Answer:

x = 2, x = 0

Step-by-step explanation:

If the solution for both functions is the same, f(x) and g(x) should have the same number. Hence, by looking at the table, both functions have -3 as the answer when x =0. Moreover, both functions have 0 as the answer when x = 2. Hence the answer is x = 0 and x = 2

4 0
3 years ago
(19 – 6) x [ 19 + { 15 + 8 – 3 } ]
Marianna [84]

Answer:

117

Step-by-step explanation:

=(3)×[19+{15+8-3}]

=3×[19+{23-3}]

=3×[19+20]

=3×39

=117

4 0
3 years ago
En la finca de los padres de un amigo han sacado un total de 18.367,42 kg de aceitunas. Ellos tienen 648 olivos. ¿Cuántos kg de
ElenaW [278]

Answer:

Promedio de kg por arbol= 28.35kg

Step-by-step explanation:

Dada la siguiente información:

Cantidad de árboles= 648

Cantidad total de kg= 18.367,42 kg

<u>Para calcular el promedio de kg por arbol, tenemos que usar la siguiente formula:</u>

<u></u>

Promedio de kg por arbol= cantidad total de kg / número de arboles

Promedio de kg por arbol= 18.367,42 / 648

Promedio de kg por arbol= 28.35kg

3 0
3 years ago
If AB is parallel to CD and the slope of CD is -5, what sis the slope of AB?
Lady bird [3.3K]

Answer:

The answer is D. -5

Step-by-step explanation:

Since AB is parallel to CD, their slopes are the same. Parallel actually means to have the same slope.

7 0
3 years ago
Read 2 more answers
The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the
ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/\sqrt{n})

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/\sqrt{n}

The upper limit => C.I_u = μ + Z*σ/\sqrt{n}

The lower limit => C.I_l = μ - Z*σ/\sqrt{n}

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/\sqrt{n})

                                    = 200 + (1.96*30)/\sqrt{n}

                                    = 200 + 58.8/\sqrt{n}

5 0
3 years ago
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