How do I do question 6?
1 answer:
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Answer:
Choice D
Step-by-step explanation:
The function will be continuous everywhere except where the function in the denominator is 0. We, therefore determine the value(s) of x for which the function will be 0;
Therefore, the points x= 2 and x =4 are points of discontinuity
Hello,
-2<1 ==> f(x)=3x²-1 =>f(-2)=3*(-2)²-1=3*4-1=12-1=11
-2<1 ==> f(x)=3x²-1 =>f(-2)=3*(-2)²-1=3*4-1=12-1=11