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MAVERICK [17]
3 years ago
6

How do I do this, I need to show work

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0
Hello,

-2<1 ==> f(x)=3x²-1 =>f(-2)=3*(-2)²-1=3*4-1=12-1=11

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Step-by-step explanation:

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2 years ago
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Simplify; 1/x^2+5x+6 + 1/x^2+3x+2<br><br> pls I need a step by step solution urgently
ikadub [295]

Answer:

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

Step-by-step explanation:

To add two algebraic fractions do these steps

  1. Factorize each denominator
  2. Simplify each fraction to its lowest term
  3. Find the LCM of the two denominators
  4. Divide LCM by each denominator and multiply the numerators by its corresponding quotients
  5. Add the two fraction and simplify the last answer

To simplify \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}

Factorize each denominator

∵ The denominator of the first fraction is x² + 5x + 6

∵ x² = (x)(x)

∵ 6 = (2)(3)

∵ (2)(x) + (3)(x) = 5x ⇒ middle term

∴ x² + 5x + 6 = (x + 2)(x + 3)

∵ The denominator of the second fraction is x² + 3x + 2

∵ x² = (x)(x)

∵ 2 = (2)(1)

∵ (2)(x) + (1)(x) = 3x ⇒ middle term

∴ x² + 3x + 2 = (x + 2)(x + 1)

Find the LCM of the two denominators

∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)

- LCM is all the <u><em>different factors</em></u> multiplied together

∴ LCM of them is (x + 1)(x + 2)(x + 3)

- Divide LCM by each denominator

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)

- Multiply the numerator of the first fraction by (x + 1)

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)

- Multiply the numerator of the second fraction by (x + 3)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{x+1}{(x+1)(x+2)(x+3)}+\frac{x+3}{(x+1)(x+2)(x+3)}

- Add the numerators and write the answer as a single fraction

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2x+4}{(x+1)(x+2)(x+3)}

- Factorize the numerator by taking 2 as a common factor

∵ 2x + 4 = 2(x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2(x+2)}{(x+1)(x+2)(x+3)}

- Simplify the fraction by dividing up and down by (x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2}{(x+1)(x+3)}

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

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3 years ago
Jill has a 25% off coupon for some computer software. If the coupon saved her $35, how much would the software cost without the
zysi [14]

Answer:

$140

Step-by-step explanation:

35 times 4

6 0
3 years ago
D Question 5 5. Given A is between Y and Z and YA = 14x, AZ = 10x and YZ = 12x + 48, find AZ<br>​
Anna007 [38]

Answer:

Step-by-step explanation:

If A is in between Y and Z, then;

YA+AZ = YZ

Given.

YA = 14x,

AZ = 10x and

YZ = 12x + 48

Substitute into the formula

14x+10x = 12x+48

Find x;

24x = 12x+48

24x-12x = 48

12x = 48

x = 48/12

x = 4

Get AZ

AZ = 10x

AZ =10(4)

AZ = 40

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3 years ago
Find f(-5) of f (x) = x + 1<br> 1) 4<br> 2) 5<br> 6) 6
Alex
F(-5) just means that your substituting the number -5 for every x value. So if you have x+1 this would be -5+1 which is -4
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3 years ago
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