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4 years ago

Which of the following is the correct graph of the liners equation y+2=1\5 (x-1

Mathematics

1 answer:

Rom4ik [11]4 years ago

5 0

There are no options

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m<1=6x and m<3= 120. find the value of x for p to be parallel to q. the diagram is not to scale

lord [1]

M<1 = M<3
these 2 angles are equal for parallel lines
6x=120
X=120/6=20

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4 years ago

*HELP*

romanna [79]

Answer: an average resulting from the multiplication of each component by a factor reflecting its importance.

Step-by-step explanation:

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3 years ago

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A research article reports the results of a new drug test. The drug is to be used to decrease vision loss in people with Macular

Brilliant_brown [7]

Answer:

A. Valid

Step-by-step explanation:

The P-value is the probability of getting this result or sample statistic if the null hypothesis is true. That is why a low P-value (smaller than the significance level) is considered evidence to reject the null hypothesis, because the result has little probability of being due to chance.

The statement that the P-value is "the probability of getting results as extreme as or more extreme than the ones in this study if the drug is actually not effective" is valid, as the null hypothesis states generally the opposite of the objective of the study (demonstrate that the drug is effective), and the very low value of the P-value is indicative that this result, if the drug was not effective, has a very low probability.

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4 years ago

Please answer my question in the comments

lidiya [134]

Answer: c

Step-by-step explanation:

I would say c because it explains what it's saying and looks like it will show the answer by saying how many more

3 0

3 years ago

Help i dont understand how to complete this

Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

Step-by-step explanation:

$Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8$

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9 --> 10.8 + 9 = 19.8

Danny: x --> 10.8

****************************************************************************************

2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3 (x = -1 is an extraneous solution so is not valid)

2d) No Solution (x = 1 is an extraneous solution so is not valid)

Here is the work for 2a. Follow this format for b, c, & d

$\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}$

$x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}$

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3 years ago