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3 years ago

1 gallon of water boils at 100 degree Celsius (Cº). 4 gallons of water will boil at __________

1 answer:

3 0

It’s 100° celsius as an intensive property i think but you might wanna search up the difference between intensive and extensive :)

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The set of chemical and physical properties of a ______ are different from those of its constituents.

Veronika [31]

Answer:

compound

Explanation:

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3 years ago

Whats does x stand for?

Furkat [3]

x is the chemical symbol of the element and it must correspond to the atomic number

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3 years ago

First to answer both CORRECTLY gets brainleist!

madam [21]

Answer: I am actually studying about Stars, so I got you.

3. As the temperature of a star Increases, it's luminosity increases.

As the temperature of a star decreases, it's luminosity decreases.

4. Hot and Bright. The bigger the star, the hotter it gets is from what I learned.

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3 years ago

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Which sub-atomic particle is NOT found at the center of the atom?

Ostrovityanka [42]

All the positive charge of an atom is contained in the nucleus, and originates from the protons. Neutrons are neutrally-charged. Electrons, which are negatively-charged, are located outside of the nucleus.

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4 years ago

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If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p

Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

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3 years ago

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