All categories

3 years ago

What is the name of a solution where no more solute will dissolve

Chemistry

1 answer:

neonofarm [45]3 years ago

5 0

Saturated solution .

You might be interested in

Is this correct? This is stoichiometry.

Viefleur [7K]

Yes it’s is bc I said so

7 0

3 years ago

A certain mass of nitrogen gas occupies a volume of 7.56 L at a pressure of 5.08 atm. At what pressure will the volume of this s

faust18 [17]

Answer:

P₂ = 3.86 atm .

Explanation:

We assume that during this change , the temperature of the gas remains constant .

So the gas will obey Boyle's law .

P₁ V₁ = P₂V₂

5.08 x 7.56 = P₂ x 9.94

P₂ = 3.86 atm .

8 0

3 years ago

Which structural adaptation would help a plant survive better in a shady environment?

Gekata [30.6K]

Answer:C.

large leaves

Explanation: I took the test

3 0

3 years ago

Ne4ueva [31]

Answer:

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

Explanation:

Volume of cylindrical reservoir = V

Radius of the cylindrical reservoir = r = d/2

d = diameter of the cylindrical reservoir = d = $4.50\times 10^1 m=45 m$

r = d/2 = 22.5 m

Depth of the reservoir = h = 10.0 m

$V=\pi r^2 h$

$=3.14\times (22.5 m)^2\times 10.0 m=15,896.25 m^3=15,896,250 L$

$1 m^3=1000 l$

Volume of water cylindrical reservoir : V

Density of water,d = 1 kg/L

Mass of water cylindrical reservoir = m

$m=d\times V=1 kg/L\times 15,896,250 L=15,896,250 kg$

1.6 kilogram of fluorine per million kilograms of water. (Given)

Concentration of fluorine in water = 1.6 kg/ 1000,000 kg of water

In 1000,000 kg of water = 1.6 kg of fluorine

Then $15,896,250 kg$ of water have x mass of fluorine:

$\frac{x}{15,896,250 kg\text{kg of water}}=\frac{1.6 kg}{1000,000 \text{kg of water}}$

$x=\frac{1.6 kg}{1000,000}\times 15,896,250 kg=25.434 kg$

15,896,250 kg water of contains mass 25.434 kg of fluorine.

25.434 kg = 25434 g

25,434 grams of fluorine should be added to give 1.6 ppm.

Percentage of fluorine in hydrogen hexafluorosilicate :

Molar mass hydrogen hexafluorosilicate = 144 g/mol

$F\%=\frac{6\times 19 g/mol}{144 g/mol}\times 100=79.16\%$

Total mass of hydrogen hexafluorosilicate = m'

$79.16\%=\frac{25,434 g}{m'}\times 100$

m' = 32,127.02 g

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

5 0

3 years ago

Reading the Temperature of Thermometers

Anna71 [15]

Answer:37.0,42.5

Explanation:

3 0

3 years ago