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katrin [286]
3 years ago
9

You collect a sample of gases from an indoor pool area. The sample contains air and water vapor. The total pressure is 100.18 ki

lopascals, and the partial pressure of the water vapor is 3.36 kilopascals. What is the partial pressure of the air in the sample?
A. 29.8 kPa
B. 51.77 kPa
C. 96.82 kPa
D. 103.54 kPa
E. 337 kPa
Chemistry
2 answers:
nikitadnepr [17]3 years ago
7 0

Here we have to choose the partial pressure exerted by the air in the given sample among the given options.

The partial pressure of the air in the sample is C. 96.82 kPa.

As per the Dalton's law of partial pressure the total pressure of the gas in the pool (P) is equivalent to the summation of the partial pressure of water vapor and air pressure.

Mathematically we may write:

P_{Total}= P_{water vapor} +  P_{Air}

Now the P_{Total} = 100.18 kilopascalsP_{water vapor} = 3.36 kilopascals.On plugging the values:100.18 kilopascals = 3.36 kilopascals + P_{Air}

Or, P_{Air}[/tex] = (100.18 - 3.36) kilopascals

Or, P_{Air}[/tex] = 96.82 Kilopascals.

Thus the partial pressure of the air in the sample is C. 96.82 kPa.

gogolik [260]3 years ago
4 0

Thus the partial pressure of the air in the sample is C. 96.82 kPa.

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Answer:

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General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<u>Organic</u>

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<u>Stoichiometry</u>

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Explanation:

<u>Step 1: Define</u>

[RxN - Unbalanced] CH₄ + O₂ → CO₂ + H₂O

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 130 g CH₄

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[RxN] 1 mol CH₄ → 2 mol H₂O

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<u>Step 3: Stoichiometry</u>

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  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 9.75526 \cdot 10^{24} \ molecules \ H_2O

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Given :

A compound has a molar mass of 129 g/mol .

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Solution :

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