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Advocard [28]
3 years ago
10

A) Earlier you were told that of all of the 14 solutes you will be studying, the only one that is not appreciably ionized in wat

er is aqueous ammonia. What does this statement imply about the equilibrium point of the reaction involving aqueous ammonia/ammonium hydroxide?B) Use your results and conclusions from part (a) to explain why a complicated name like Aqueous ammonia/ammonium hydroxide is used for this solution?
Chemistry
1 answer:
lidiya [134]3 years ago
4 0

Answer:

Throughout the overview section following portion, the description and according to particular circumstance is defined.

Explanation:

As per the question,

⇒ NH_3(aq)+H_2O\leftrightarrow NH_4+(aq)+OH-(aq)

  • A weak basis seems to be NH3. It serves as a base since the aqueous solution or phase is protonated. But NH3 +, just becoming a weak base, is therefore deprotonated into form NH3, and therefore also 90% of ammonia becomes found throughout NH3 state in aqueous solution.  

⇒ NH_3+(aq) \leftrightarrow NH_3(aq)+H+(aq)

However, it is also available in NH3 form throughout the aqueous solution much of the moment.

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I first converted the given grams of the reactants into moles, and then divided the moles by the coefficients in front of each of the reactant. The result with the smallest value will be the limiting reactant, and the value of CuO was the smallest, so it's the limiting reactant.

After figuring out which reactant is the limiting one, I took their given grams and converted it into moles, the divided it by the ratio of N2 to CuO (it's in the equation) to obtain the moles of N2, and then multiply it with the molar mass of N2 to get its mass in grams.

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One year ago, you sold a put option on 100,000 euros with an expiration date of 1 year. you received a premium on the put option
pochemuha
There are two problems for this question:1. What is the total dollar amount of your profit and loss:
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Net profit is = 0.02 x 100,000 = 2,000 – 80 = 1,920

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