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Luba_88 [7]
3 years ago
14

I need help with 1-2 please help

Mathematics
1 answer:
valkas [14]3 years ago
7 0
1. The dimensions of the rectangle are 3 units by 4 units.

2. 0.3 x 0.4 = 0.12
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Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8.
svetoff [14.1K]
D -3m-4n+14. Once you write out the equation, you have to combine all the like terms, also known as simplifiying
6 0
3 years ago
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Evaluate the integral x^3 (x 4 −8)^44 dx by making the substitution u = x^4 - 8
Eduardwww [97]

Answer:

(x^4-8)^45 /180 +c

Step-by-step explanation:

If u=x^4-8, then du=(4x^3-0)dx or du=4x^3 dx by power and constant rule.

If du=4x^3 dx, then du/4=x^3 dx. I just divided both sides by 4.

Now we are ready to make substitutions into our integral.

Int(x^3 (x^4-8)^44 dx)

Int(((x^4-8)^44 x^3 dx)

Int(u^44 du/4)

1/4 Int(u^44 dul

1/4 × (u^45 / 45 )+c

Put back in terms of x:

1/4 × (x^4-8)^45/45 +c

We could multiply those fractions

(x^4-8)^45 /180 +c

5 0
3 years ago
Select all of the statements that are true for the given parabola.
Masja [62]

Answer:

A and B are true

Step-by-step explanation:

The minimum is the turning point on the graph and occurs at (1, - 2)

The x- intercepts are where the graph crosses the x- axis , that is at

x = - 1 and x = 3 or in coordinate form (- 1, 0 ) and (3, 0 )

The equation of the axis of symmetry is a vertical line passing through (1, - 2)

with equation x = 1

The true statements are A and B

6 0
3 years ago
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Suppose that a random sample of size 36 is to be selected from a population with mean 50 and standard deviation 7. What is the a
frez [133]

Answer:

The probability that the sample mean will be within 0.5 of the population mean is 0.3328.

Step-by-step explanation:

It is provided that a random variable <em>X</em> has mean, <em>μ</em> = 50 and<em> </em>standard deviation, <em>σ</em> = 7.

A  random sample of size, <em>n</em> = 36 is selected.

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu=50

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{7}{\sqrt{36}}=1.167

So, the distribution of the sample mean of <em>X</em> is N (50, 1.167²).

Compute the probability that the sample mean will be within 0.5 of the population mean as follows:

P(|\bar X-\mu_{\bar x}|\leq 0.50)=P(-0.50

                               =P(\frac{-0.50}{1167}

Thus, the probability that the sample mean will be within 0.5 of the population mean is 0.3328.

4 0
4 years ago
Answer please.tyyyyy
Kazeer [188]

Answer:

30=2r+r

r=5

Step-by-step explanation:

30=2r+r would be the answer for the first question because the red line, 30, is equal to the line 2r and r.

r=7.5 because 30=2r+r (combine like terms)➡️ 15=3r (divide both sides by 3)➡️  5=r

4 0
4 years ago
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