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Alenkasestr [34]

4 years ago

11

EXPERT/ACE/TRUSTED HELPERS HELP ASAP

1 answer:

Alla [95]4 years ago

7 0

The vertex of the original is (0,)

The vertex for Part A is (4,12)

The vertex for part B is (-8,-9)

So both vertex are shifted according to the numbers in the equation.

the number inside the parenthesis with x shifts the graph left or right. Subtraction moves it right, addition moves it left

so (x-4) moves it 4 units to the right and (x+8) moves it 8 units to the left.

Then the numbers after the parenthesis move the graph up or down. Adding moves it up, subtraction moves it down.

+12 moves the graph 12 units up, -9 moves the graph 9 units down.

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The graph of y = x 2 has been translated 7 units to the left. The equation of the resulting parabola is _____.

strojnjashka [21]

To move the function to the left you have to increase x inside the function
think of it like g(x)=f(x+7)

the solution is
y=(x+7)^2

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yulyashka [42]

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ira [324]

Answer:

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8 0

3 years ago

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Please help fast! give me the equation

uranmaximum [27]

$\begin{bmatrix}x=\frac{\pi }{2}+2\pi n\\ x=\frac{3\pi }{2}+2\pi n\\ x=\frac{3\pi }{4}+\pi n\\ x=\frac{7\pi }{4}+\pi n\end{bmatrix}$

$\begin{bmatrix}\frac{3\pi }{2}+2\pi n=\frac{\pi }{2}+2\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{3\pi }{4}+\pi n\\ \frac{3\pi }{2}+2\pi n=\frac{7\pi }{4}+\pi n\end{bmatrix}$

$\pi =0$

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6 0

3 years ago

What is the common difference of the sequence 8, 4, 0, -4, -16?

soldier1979 [14.2K]

$\large \mathfrak{Solution : }$

Common difference of an Arithmetic progression can be found out by subtracting the preceding term from that given term.

i.e

$common \: \: difference = 4 - 8$
$common \: \: difference = - 4$

therefore, the common difference of the above Arithmetic progression is -4 .

7 0

3 years ago