50% were invested in land, 10% were invested in stocks and 20% were invested in bonds.
Based on this, the total percentage of investments can be calculated as follows:
percentage of investments = 50% + 10% + 20% = 80%
The remaining percentage that was put into a saving account can be calculated as follows:
percentage of money in saving account = 100% - 80% = 20%
Now we know that the remaining is $35,000 represent the 20% of his money.
Assume his total amount of money is m, therefore:
20% x m = 35000
0.2m = 35,000
m = (35,000) / 0.2 = 175,000
Based on this, <span>the total amount of money that Mr. Rodriguez saves and invests is $175,000</span>
It would be 4.5
Hope this helps.
First do 4.04 mil - 3.66 mil to get .38 mil (which is 380 thousand) then divide 380,000/10 to get answer J. 38,000. Hope this helped
Answer:
- a(x) = 20 + 0.60x
- domain [0, 50]; range [20, 50]
- maybe
Step-by-step explanation:
a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...
0.40 × (50 -x)
The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...
1.00 × (x)
Then after the remove/replace operation, the total amount of acid in the container is ...
a(x) = 0.40(50 -x) +1.00(x)
a(x) = 20 +0.60x . . . . . liters of acid in the final mixture
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b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)
The associated range is 20 ≤ a ≤ 50. (liters)
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c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.