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romanna [79]
2 years ago
6

I'm in need of some desperate help ​

Mathematics
1 answer:
mojhsa [17]2 years ago
6 0

Answer:

77/134 or 0.5746

Step-by-step explanation:

The approximate relative frequency is "the number of times that the event occurs during experimental trials, divided by the total number of trials conducted."

So we need to identify the number of times the event occured, the amount of times children chose sweet snacks, and the total number of trials conducted. So since the question wants the approximate relative frequency by column, we use the number 134 for the total number, and 77 for the number of times the event occurred. We then divide 77 by 134, which looks like this: 77/134. In decimal form, this equals 0.5746. It can't be simplified anymore in fraction form, so 77/135 would be another way to answer.

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lord [1]

Answer:

The denominators are not equal.

Step-by-step explanation:

7 0
2 years ago
Two equations are given below:
astraxan [27]
A - 3b = 4
a = b -2

(b - 2) - 3b = 4
b - 2 - 3b = 4
-2b = 4 + 2
-2b = 6
b = 6/-2
b = -3

a = b - 2
a = -3 -2
a = -5

to check: a = -5 ; b = -3  
⇒ (-5,-3)
a - 3b = 4
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4 0
3 years ago
Someone please help me answer this!!
dybincka [34]

Answer:

17.9 units is the answer

Step-by-step explanation:

points are (-7,-2) and (9,6)

Pythagorean theorem can be written as,

d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d=\sqrt{9-(-7))^2 + (6-(-2))^2}\\\\d=\sqrt{(16)^2+(8)^2} \\\\d=\sqrt{256+64} \\\\d=\sqrt{320} \\\\d=17.88

Rounding off,

d = 17.9 units

7 0
3 years ago
Help!! Below, the two-way table is given for a<br> class of students.<br> Brainliest!!
UNO [17]
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6 0
2 years ago
which function has real zeros at x = −10 and x = −6? f(x) = x2 16x 60 f(x) = x2 − 16x 60 f(x) = x2 4x 60 f(x) = x2 − 4x 60
LiRa [457]

Answer:

Option A is correct

The function x^2+16x+60 has real zeroes at x =-10 and x =-6

Explanation:

Given: The real zeroes or roots are x = -10, and x = -6

To find the quadratic function of degree 2.

x^2- (\alpha+\beta)x + \alpha\beta =0 where α,β are real roots.   ....[1]

Here, α= -10  and β= -6

Sum of the roots:

α+β =  -10+(-6) = -10-6 = -16

Product of the roots:

αβ = (-10)(-6)= 60

Substitute these value in equation [1] we have;

x^2-(-16)x+60 = x^2+16x+60

Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;

x^2+16x+60

8 0
2 years ago
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