5x 3y^3 2z
I know it is in standard form because there are no more like terms.
Part B: Polynomials are always closed under multiplication. Unlike with addition and subtraction, both the coefficients and exponents can change. The variables and coefficients will automatically fit in a polynomial. When there are exponents in a multiplication problem, they are added, so they will also fit in a polynomial.
Or,
Refer to the photos:
hope this help :)
Answer: Third option.
Step-by-step explanation:
By definition, Rational Functions have the following form:

Where
and
are polynomials.
The Restrictions of the Domain of Rational Functions are those Real numbers that make the denominator equal to zero, because the division by zero is not defined.
In this case, you have the following Rational Function:

The Restrictions of the Domain can be found applying this steps:
- Make the denominator equal to 0:

- Solve for "x":

Then, the Domain of this function includes all "x" not equal to 2.
Therefore, the answer is:
Answer:
Explanation:
• The initial dose of the Insulin = 10 Units
The insulin breaks down by about 5% each minute, therefore:
• The decay rate, r= 5%
We want to determine the time it will take for the remaining dosage to be half (5 units) of the original dose.
We use the exponential decay function:

Substituting the given values, we have:

To solve for t, we change to logarithm form.
The value of given expression when m = 3 is 27
<h3><u>Solution:</u></h3>
Given expression is 
We have to evaluate the given expression for m = 3
To find for m is equal to 3, substitute m = 3 in given expression
From given expression,

Plug in m = 3 in above expression
------ eqn 1
We know that,
can be expanded as,

Applying this in eqn 1, we get

Simplify the above expression

Therefore, for m = 3 we get,

Thus value of given expression when m = 3 is found
Answer:
39,917,124
Step-by-step explanation:
In order to solve this problem we must start by drawing a diagram of what the licence plates look like. (See Attached picture).
Now, each box in the picture will represent one digit of the plate. Some must be numbers and some must be letters. We know we have 9 posibilities for theh numbered boxes (1-9) and we have 26 possibilities for the boxes that are to contain letters. Repetitions allowed. So the possible character for each box is as follows:
box 1 = 1 to 9 = 9
box 2 = A to Z = 26
box 3 = A to Z = 26
box 4 = 1 to 9 = 9
box 5 = 1 to 9 = 9
box 6 = 1 to 9 = 9
box 7 = 1 to 9 = 9
so the total number of licence plates can be found by multiplying the possibilities for each box in the plate so we get:
# of plates = (9)(26)(26)(9)(9)(9)(9)
which can be simplified to:
