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ollegr [7]
3 years ago
15

7th grade please explain not just the answer sorry its blurry

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
6 0
<h3>Hey there! </h3><h3>You could simply solve this equation by doing PEMDAS </h3><h3>Parentheses </h3><h3>Exponents </h3><h3>Multiplication </h3><h3>Division </h3><h3>Addition </h3><h3>Subtraction </h3><h3>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3><h3>(-5)^2 -2*(-9) +6</h3><h3>(-5)^2 = (-5) (-5) </h3><h3>(-5)(-5) =25</h3><h3>25 - 2(-9) +6 </h3><h3>2(-9) = -18</h3><h3>25 - (-18) +6 </h3><h3>We have DOUBLE <u>negatives</u>, so this means we have a <u> positive result </u></h3><h3>25 + 18 = 43 </h3><h3>43 + 6 = 49</h3><h3>Answer/ Result: 49 </h3><h3>Good luck on your assignment and enjoy your day! </h3><h3>~LoveYourselfFirst:)</h3>
aleksandrvk [35]3 years ago
3 0

Answer:

25-(-18)+6

=25+18+6

=49

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Someone please help.
Alexxandr [17]

Hi there!

f(x)+f(x+1)=4f(x)

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that  f(x)=3^x:

⇒ f(x)=3^x:

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function f(x)=3^x:

⇒ f(x+1)=3^x^+^1

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function f(x)=3^x by 4:

4f(x)=4*3^x:

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation f(x)+f(x+1)=4f(x):

f(x)+f(x+1)=4f(x)

3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x

Factor the left side

3^x*(1+3)=4*3^x

Divide both sides by 3^x

1+3=4\\4=4

Because this equation is true, f(x)+f(x+1)=4f(x) is therefore true.

I hope this helps!

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