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3 years ago

Lin was looking at the equation 2x − 32 + 4(3x − 2462) = 14x.

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Answer: Lin is correct but her thinking is wrong.

Step-by-step explanation:

2x-32+4(3x-2462)=14x

First solve parentheses: 2x-32+12x-9842=14x (you distribute the 4).

Then add common factors on the same side of the equal signs:

14x-9880=14x

When solving for x you would subtract 14x giving you:

-9880=0 which would never be true.

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Solve the expressions on the left when x=5<br>3x-10<br>x^2-15<br>5x-21<br>x+10-8

Nitella [24]

Answer:

Step-by-step explanation:

Apply the value of x into the expressions:

3(5) - 10 = 15 - 10

= 5

5² - 15 = 25 - 15

= 10

5(5) - 21 = 25 - 21

= 4

5 + 10 - 8 = 15 - 8

= 7

5 0

3 years ago

Read 2 more answers

There are 7 girls and 9 boys on a playground.

Anon25 [30]

The ratio of the number of girls to the total number of children is 7 : 16.

<h3>Ratio is defined as follows:</h3>

It is a comparison between two or more numbers that measures sizes in relation to each other
It describe how much of a thing is compared to another.

The number of girls in the playground = 7

The number of boys in the playground = 9

The total number in the playground is the sum of the number of girls and the number of boys.

Therefore,

total children in the playground = 7 + 9 = 16

The ratio of the number of girls to the total number of children can be express as follows:

Ratio = 7 : 16

learn more on ratio here: brainly.com/question/26169121?referrer=searchResults

8 0

2 years ago

Read 2 more answers

Please help me with this question

Vinvika [58]

Tan(angle) = opposite/adjacent
tan(x) = 90/51
x = arctan(90/51)
x = 60.461217740442
which rounds to 60 when rounding to the nearest whole number

Answer: 60

3 0

3 years ago

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

Yall know the rate of change?

ale4655 [162]

Answer:

M=-3

Step-by-step explanation:

Slope:

y2-y1/x2-x1

-3-3/1+1=6/-2=-3

4 0

2 years ago