All categories

3 years ago

HELP PLEASE IS FOR TODAY

Mathematics

1 answer:

babunello [35]3 years ago

5 0

Answer:

It's A. segment A"B" is closer to segment C than segment A"B".

Step-by-step explanation:

You might be interested in

Plz help thank you<br> correct ans only

kakasveta [241]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

today, 6 friends went out for lunch. their total Bill was $41.88, including tax and gratuity. they decide to split the Bill equa

Mariulka [41]

Each person will get back $3.02

4 0

3 years ago

Read 2 more answers

Total revenue is 3,000 cost of goods 1,500 total selling expence is 500 what is profit

12345 [234]

Cost of goods = 1,500
Selling expense = 500

Total cost in selling = 1500 + 500 = 2000

Profit = Total Revenue - Total cost in selling = 3000 - 2000 = 1000

Profit = 1000

Hope this explains it.

8 0

3 years ago

Read 2 more answers

Due to a leak, the amount of water in a pool is decreasing by 5858 gal every hour.

Dafna1 [17]

Here is the solution to the given problem above.
Given the the amount of water in a pool is decreasing 5/8 gallon every hour.
And what would be the change in the number of gallons after 3/4 hour. So what we are going to do is just to multiply 5/8 by 3/4. And the result would be 15/32. The total change in the number of gallons of water in the pool after 3/4 hour would be 15/32 gallons.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

2 years ago