Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
rise over run
Step-by-step explanation:
Answer:
x = 0
x = 3
Step-by-step explanation:
Answer:
B. 41.8° is the correct answer
Step-by-step explanation:
We are given that,
Length of Eduardo's flight path = 273 miles
Length of Paul's flight path = 357 miles
Distance between their destinations = 238 miles.
Now, using the law of cosines, we get,
i.e.
i.e.
i.e.
i.e.
i.e.
i.e. θ = 41.8°
Hence, the angle between their flight paths is 41.8°.