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3 years ago

I need plz help fast

Mathematics

1 answer:

Bad White [126]3 years ago

3 0

Answer:

Step-by-step explanation:

24a²b³ - 28a⁵b³

apply exponential rule:

24a²b³ - 28a²a³b³

re-write 24 as 6*4 and -28 as 7*4

6*4a²b³ + 7*4a²a³b³

factor common terms

-4a²b³ (-6+ 7a³)

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4 years ago

What’s the answer ? Please help

Romashka [77]

Answer:

Step-by-step explanation:

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3 years ago

A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase

il63 [147K]

Answer:

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

The question is incomplete. The complete question is:

"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said ‘‘yes”. Use this information to find a 90% confidence interval for the difference in the two proportions, pm - pw. Subscript pm is the proportion of men who support the proposed law and pw is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

$p_m=X_m/n_m=318/520=0.612$

The sample 2, of size nw= has a proportion of pw=0.824.

$p_w=X_w/n_w=379/460=0.824$

The difference between proportions is (pm-pw)=-0.212.

$p_d=p_m-p_w=0.612-0.824=-0.212$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711$

The estimated standard error of the difference between means is computed using the formula:

$s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029$

Then, the margin of error is:

$MOE=z \cdot s_{pm-pw}=1.645\cdot 0.029=0.0477$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.212-0.0477=-0.260\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.212+0.0477=-0.165$

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

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3 years ago

What is the expasion of (2x + 3)^3 ?

Marianna [84]

Answer:

(2x + 3)3

Step-by-step explanation:

Simplify: (2x+3)(3)

Answer: (2x + 3)3

Hope this helps.

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3 years ago

You purchased a new sports car 40 years ago at a cost of $5,167.55. Today, you sold that car for $97,500. What annual rate of re

bezimeni [28]

Based on the given values above, if you purchase a new sports car 40 years ago at a cost of $5,167.55 and sold it for $97,500, this would mean that the annual rate of return you earned on the vehicle is 5%. Hope this answers your question. Have a great day!

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3 years ago