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Diano4ka-milaya [45]
3 years ago
15

HELP PLS 20 PTS PLSSSSSSSSSSS

Mathematics
2 answers:
Rama09 [41]3 years ago
5 0

Answer:

(9,9)

Step-by-step explanation:

kolezko [41]3 years ago
4 0
I think so...
D(15,11)

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Solve this quadratic equation. Show all work. <br><br><br> 4x^2-2x-5=0
kicyunya [14]
X= -b⁺₋ √b²-4ac/2a
x= (-(-2)⁺₋√(-2)²- 4(4)(-5))/2(4)
x= 4 ⁺₋√4+80/8
x= (4⁺₋ 9.165)/8
x= 4+9.165)/8 or x= 4-9.165)/8
x= 1.40 or x= -0.896

6 0
3 years ago
Please explain thoroughly.
mixas84 [53]

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5 0
3 years ago
Comppete the equation <br> X^2+y^2-10x+6y=15
mart [117]
I believe you meant:  Use completing the square to determine the center and radius of the circle represented by this equation:   <span>X^2+y^2-10x+6y=15

x^2 - 10x + 25 - 25 + y^2 + 6y + 9 - 9 = 15
Then:
     (x-5)^2               +   (y+3)^2            = 24   = 2sqrt(6)

This circle is centered at (5,-3) and has radius 2sqrt(6).</span>
8 0
4 years ago
Find the equation of line b described below, in slope-intercept form
Serjik [45]

Given:

Line a is perpendicular to line b .

Line a passes through the points (1,-8) and (9,-12) .

Line b passes through the point (-8, -16).

To find:

The equation of b.

Solution:

Line a passes through the points (1,-8) and (9,-12) . So, slope of line a is

m=\dfrac{y_2-y_1}{x_2-x_1}

m_a=\dfrac{-12-(-8)}{9-1}

m_a=\dfrac{-12+8}{8}

m_a=\dfrac{-4}{8}

m_a=-\dfrac{1}{2}

Product of slopes of two perpendicular lines is -1.

m_a\times a_b=-1

-\dfrac{1}{2}\times a_b=-1

b=2

Slope of line b is 2.

If a line passing through a point (x_1,y_1) with slope m, then equation of line is

y-y_1=m(x-x_1)

Line b passing through (-8,-16) with slope 2. So, equation of line b is

y-(-16)=2(x-(-8))

y+16=2(x+8)

y+16=2x+16

Subtract 16  from both sides.

y=2x

Therefore, the equation of line b is y=2x.

7 0
3 years ago
Volume is a three-dimensional measure.<br> true<br> false
Xelga [282]
True, volume is a tree dimensional measure.
7 0
3 years ago
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