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Genrish500 [490]
3 years ago
8

Suppose that a normal distribution has a mean of 20 and a standard deviation of 4. What is the z-score of 13?

Mathematics
1 answer:
Papessa [141]3 years ago
5 0

Answer:

-1.75.

Step-by-step explanation:

The z-score = (n - m) / d  where n is the value (13) m = mean and d = standard deviation.

= (13 - 20) / 4

= -1.75  (answer)

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Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

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- 21 = - 12 – 9  

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L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

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L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

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3 years ago
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