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alukav5142 [94]
2 years ago
7

What’s the correct answer for this?

Mathematics
2 answers:
goblinko [34]2 years ago
5 0
5x + 34 = -2(1 - 7x)
5x + 34 = -2 + 14x
36 = 9x
x = 4
NO = -2(1 - 7*4)
NO = -2(1 - 28)
NO = -2 + 56
NO = 54
uysha [10]2 years ago
4 0

Answer:

54

Step-by-step explanation:

Since diameter AB divides MN into two equal parts hence

MO = NO

NOW,

5x+34 = -2(1-7x)

5x+34 = -2+14x

34+2 = 14x-5x

36 = 9x

Dividing both sides by 9

x = 4

Now,

NO = -2(1-7(4))

NO = -2+56

NO = -2+56

NO = 54

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What is the measure of angle k?
Murljashka [212]

9514 1404 393

Answer:

  59°

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

  ∠N +∠L = 180°

  (a +16) +(a -18) = 180

  2a = 182 . . . . . . . . . . add 2

  a = 91 . . . . . . . . . . . . divide by 2

Then the measure of angle M is ...

  ∠M = (a+30)° = (91 +30)° = 121°

and angle K is its supplement.

  ∠K = 180° -121°

  ∠K = 59°

8 0
2 years ago
What is the mean absolute deviation<br> of the following set of data?<br> 10<br> 4<br> 2<br> 4.
fredd [130]

Answer:

80

Step-by-step explanation:

10+4+2+4=20 and 20×4 numbers=80

3 0
2 years ago
Please help me prove that ED is congruent to BA! I thought I had it right by proving right and vertical angles, but I’m missing
Vikki [24]

Step-by-step explanation:

\overline{DA} \text{ bisects } \overline{EB}     is given

\overline{BC} \cong \overline{EC}  definition of <u>bisect</u>

<u />\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}  are both given

<u />\angle B, \, \angle E \text{ are right angles}  definition of perpendicular

\angle B \cong \angle E   because all right angles are congruent

\angle{ACB} \cong \angle{DCE}  vertical angles are congruent

\triangle{ACB} \cong \triangle{DCE}   ASA (angle-side-angle)

\overline{ED} \cong \overline{BA}  CPCTC (corresponding parts of congruent triangles are congruent)

5 0
2 years ago
The lengths of two sides of a triangle are shown below:
oksano4ka [1.4K]

<u>Part A</u>

<u />3x^2 -2x-1+9x+2x^2 -3=\boxed{5x^2 + 7x-4}

<u>Part B</u>

<u />(5x^3 +4x^2 - x-3)-(5x^2 + 7x-4)=\boxed{5x^3 - x^2 - 8x+1}

<u>Part C</u>

No, because although they provide examples for specific polynomials being closed under addition and subtraction, there is a loss of generality.

6 0
2 years ago
How does the graph of f(x) = (x - 1)2 relate to the basic function f(x) = x??
harina [27]

Answer:

Shift 1 unit to the right, i.,e. option (c).

Step-by-step explanation:

Note: Both functions can not be represented by f(x) and square is missing in basic function.

The given basic function is

f(x)=x^2

The given function is  

g(x)=(x-1)^2

So, the given function can be written in the form of basic form as

g(x)=f(x-1)     ...(1)

The translation is defined as

g(x)=f(x+a)2+b     .... (2)

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (1) and (2), we get

a=-1,b=0

Therefore, graph of f(x) shift 1 unit to the right to get graph of g(x).

4 0
2 years ago
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