Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
5x5,150 =$<span>25,750 = Answer</span>
Deductions per dependent $5,150 times 5 in 2010
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This question should be relatively easy for a high schooler...