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raketka [301]
4 years ago
9

A deputy sheriff rides a horse while directing traffic, what energy is being used?

Physics
1 answer:
Travka [436]4 years ago
4 0

Answer:

Kinetic Energy

Explanation:

In relation to the question, as the sheriff rides a horse, the sheriff is in motion and a body in motion is said top possess kinetic energy.

Kinetic energy is that energy of the body that it gains due to the motion or speed of the body which it gains and maintains.

In other words, we can say that the amount of work needed to accelerate an object from its position of rest and set it into motion at some certain velocity.

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In my opinion I think that the answer is C sorry If I get this wrong.

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Where is the centre of mass of a system of two particles is situated?​
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In a two particle system, the center of mass lies on the center of the line joining the two particles.

4 0
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What rule does static electricity follow
Luba_88 [7]
Static electricity works when there is an imbalance of positive and negative charges, and thus causes a little spark.
3 0
3 years ago
A nonconducting sphere has radius R = 1.81 cm and uniformly distributed charge q = +2.08 fC. Take the electric potential at the
Sloan [31]

Answer:

a) V = -0.227 mV

b) V = -0.5169 mV

Explanation:

a)

Inside a sphere with a uniformly distributed charge density, electric field is radial and has a magnitude

E = (qr) / (4πε₀R³)

As we know that

V = -\int\limits^r_0 {E} \, dr

By solving above equation, we get

V = (-qr²) / (8πε₀R³)

When

R = 1.81 cm

r = 1.2 cm

q = +2.80 fC

ε₀ = 8.85 × 10⁻¹²

V = (-2.80 × 10⁻¹⁵ × (1.2 × 10⁻²)²) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²)³)

V = -2.27 × 10⁻⁴ V

V = -0.227 mV

b)

When

r = R

R = 1.81 cm

q = +2.80 fC

ε₀ = 8.85 × 10⁻¹²

V = (-qR²) / (8πε₀R³)

V = (-q) / (8πε₀R)

V = (-2.80 × 10⁻¹⁵) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²))

V = -5.169 × 10⁻⁴ V

V = -0.5169 mV

4 0
4 years ago
An object is placed 100 cm in front of a diverging lens of focal length -25cm. A converging lens of focal length 33 1/3 cm is pl
bagirrra123 [75]
We use 1/o + 1/i = 1/f  where o is the distance of the object, i as distance of the image and f is the focal length.
Substituting, <span>1/ 100 + 1 / i = - 1 /25 </span>
<span>i = - 20 cm </span>

<span>For the case of the problem,</span>

<span>o = (20 + 30)  = 50 cm </span>

<span>f = 33.33. </span>Using 1<span> / i + 1 / o = 1/f , </span><span> </span><span>i = 100 cm </span>

<span>M = magnification = - i / o </span>

<span>m1 = -(-20)/100 = 20/100 = 0.2 </span>

<span>m2 = -100/50 = -2 </span>

<span>M = m1*m2 = -2 x 0.2 = -0.4.</span>
8 0
4 years ago
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