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denis-greek [22]

2 years ago

5

If fuel consumption is 80 pounds per hour and groundspeed is 180 knots, how much fuel is required for an airplane to travel 477

nm?

1 answer:

lisov135 [29]2 years ago

5 0

Answer:

212 pounds

Explanation:

477 nm / 180 nm/hr * 80 #/hr = 212 #

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Martije has made a slight error in naming a compound monocarbon tetrabromide. What compound is she most likely naming, and what

Alik [6]

Answer: $CBr_4$ : carbon tetrabromide

Explanation:

$CBr_4$ is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for $CBr_4$ is carbon tetrabromide.

7 0

3 years ago

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7. A roller coaster’s velocity at the top of a hill is 10 m/s. Two seconds later it reaches the bottom ofthe hill with a velocit

zheka24 [161]

Answer:

7) $a=8m/s^2$

8) $a=-5m/s^2$

9) $a=-1.5m/s^2$

10) $v=29.4m/s$

Explanation:

For the problems 7, 8 and 9 we just apply the definition of acceleration, since no more information is given, which is:

$a=\frac{\Delta v}{\Delta t}=\frac{v_f-v_i}{t_f-t_i}$

So for each problem we will have:

7) $a=\frac{26m/s-10m/s}{2s}=8m/s^2$

8) $a=\frac{10m/s-25m/s}{3s}=-5m/s^2$

9) $a=\frac{0m/s-15m/s}{10s}=-1.5m/s^2$

For the problem 10, we use the equation of velocity in accelerated motion:

$v=v_0+at$

Since the ball starts from rest and the acceleration is that of gravity (we take the downward direction positive), we have:

$v=(0m/s)+(9.8m/s)(3s)=29.4m/s$

5 0

3 years ago

Part CPart complete Determine the maximum force P that can be applied without causing the two 43-kg crates to move. The coeffici

Wewaii [24]

Answer:

the maximum force will be equal to 134.84 N

Explanation:

We have given mass m = 43 kg

Coefficient of static friction $\mu _s=0.32$

Acceleration due to gravity $g=9.8m.sec^2$

We have to find the maximum force which , when applied there is no movement of crates

This maximum force will be equal to frictional force

Frictional force is given by $f=\mu mg=0.32\times 43\times 9.8=134.84N$

So the maximum force will be equal to 134.84 N

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3 years ago

According to the work-energy theorem, the amount of work done can be determined using which formula?

Tema [17]

W = KE = 1/2m(v2f-v2i) also known as D just took the test

8 0

3 years ago

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Does which object have the compacity that is the best measured in pints?

Wewaii [24]

Answer:

1 or 2

Explanation:

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3 years ago