Answer:
Explanation:
One of the first propulsion characteristics given in the example is that all engines are equal.
In this way if we have 4 engines running at the same time, it means that its capacity is 100%.
Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.
However, the question is, what would happen if 2.4 "Engines" now work.
To do this then we make a simple equivalence,
If 4 engines is the equivalent of 100%, when would it be 2.4 engines?
In this way it would mean that the body could be driven to 60% of its total.
So
Answer:
a) 0.568 kg
b) 474 kg/m³
Explanation:
Given:
Inner radius = 8.82 cm = 0.0882 m
Outer radius = 9.91 cm = 0.0991 m
Density of the liquid = 948.00 Kg/m³
a) The volume of the sphere = 
or
volume of sphere = 0.0012 m³
also, volume of half sphere = 
or
volume of half sphere = 
or
Volume of half sphere =0.0006 m³
Now, from the Archimedes principle
Mass of the sphere = Weight of the volume of object submerged
or
Mass of the sphere = 0.0006× 948.00 = 0.568 kg
b) Now, density = 
or
Density = 
or
Density = 474 kg/m³
Answer:
Option B. 5 nC
Explanation:
From the question given above, the following data were obtained:
Capicitance (C) = 100 pF
Potential difference (V) = 50 V
Quantity of charge (Q) =?
Next, we shall convert 100 pF to Farad (F). This can be obtained as follow:
1 pF = 1×10¯¹² F
Therefore,
100 pF = 100 pF × 1×10¯¹² F / 1 pF
100 pF = 1×10¯¹⁰ F
Next, we shall determine the quantity of charge. This can be obtained as follow:
Capicitance (C) = 1×10¯¹⁰ F
Potential difference (V) = 50 V
Quantity of charge (Q) =?
Q = CV
Q = 1×10¯¹⁰ × 50
Q = 5×10¯⁹ C
Finally, we shall convert 5×10¯⁹ C to nano coulomb (nC). This can be obtained as follow:
1 C = 1×10⁹ nC
Therefore,
5×10¯⁹ C = 5×10¯⁹ C × 1×10⁹ nC / 1 C
5×10¯⁹ C = 5 nC
Thus, the quantity of charge is 5 nC
Answer:
High density D answers to your questions
Because the Earth rotates through two tidal bulges every lunar day.
