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Scorpion4ik [409]

3 years ago

14

Through three noncollinear points there exists exactly one line. A. Always true B. Sometimes true C.Never true D. Cannot be dete

rmined

2 answers:

valkas [14]3 years ago

8 0

The answer of the question is b

inessss [21]3 years ago

7 0

The answer is B because the three <span>noncollinear points could exist on exactly one line, but not all the time.</span>

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M=3 6=-8 what is the answer really need help

Leno4ka [110]

The equation doesn’t make sense though.You said m=3 and 6=-8 which doesn’t really make sense.if that’s the equation then it’s false or no solution because there is no m in the equation.I’m sorry but to answer this you have to put in the EXACT equation

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4 years ago

Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms of the equation: y=(x-

ki77a [65]

Hello,

Multiplying (x-1) by (4x+2) the term in x² is x*4x=4x².
If we substract 4x² the term of y in x² will be 0.
The function is not quadratic.

Since 4x*(-1)+2*x=-2x (product of terms in x) : the function is thus linear.

Constant term is -1*2=-2

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4 years ago

You are offered an item for $13.79. If the seller states he normally sells the same item for $14.95, what percentage discount is

Aloiza [94]

8% discount.

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8 0

3 years ago

Read 2 more answers

What is 4 11/12 divided by -4 1/6?

Luden [163]

To get the result first we have to transform those fraction into improper fraction.
$4 \frac{11}{12}= \frac{4*12+11}{12}= \frac{59}{12}$
$-4 \frac{1}{6} =- \frac{4*6+1}{6}=- \frac{25}{6}$
We know that if we want to divide 2 fraction we can multiply first by inverse of second fraction. Lets do this
$\frac{59}{12}:- \frac{25}{6}= \frac{59}{12}*- \frac{6}{25} =- \frac{59*6}{12*25}=- \frac{354}{300}=- \frac{59}{30}=-1 \frac{29}{30}$ - its the answer

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3 years ago

What are the coordinates of the endpoints of the segment T'V'? T'(-3, 6) and V'(0, 3) T'(-3, 6) and V'(0, 1) T'(-1, 2) and V'(0,

bazaltina [42]

Answer:

Step-by-step explanation:

The figure required in the question is missing, the figure can be found in attachment.

Transforming points T and V according to the rule (x,y) -> (3/4x, 3/4y), we get:

T(-4, 8) -> (-4*3/4, 8*3/4) -> (-3, 6) which corresponds to T'

V(0, 4) -> (0*3/4, 4*3/4) -> (0, 3) which corresponds to V'

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3 years ago

Read 2 more answers