Step-by-step explanation:
345x19=467 that's it good luck
Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Answer:
Where are the box plots?? I need it to answer the question.
Answer:
GOOGLE
Step-by-step explanation:
GOOGLE ATE MY BONEST CHILDREN
Answer:
80
Step-by-step explanation:
Let's write out the equation:
8(20+80/2)/[(54/9+14)/4]
For the first part we get 8(100/2)
Then 50x8
Then 400
For the second part we have (6+14)/4 as we divide 54 by 9. PEMDAS
Then 20/4
Then 5
So our final answer is 400/5 which is 80.
Hope this helps!