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Olenka [21]
4 years ago
7

M=3 6=-8 what is the answer really need help

Mathematics
1 answer:
Leno4ka [110]4 years ago
5 0
The equation doesn’t make sense though.You said m=3 and 6=-8 which doesn’t really make sense.if that’s the equation then it’s false or no solution because there is no m in the equation.I’m sorry but to answer this you have to put in the EXACT equation
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2,3,6,9,18,1

Step-by-step explanation:

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Vitek1552 [10]

Answer:

d. 15 square yard

Step-by-step explanation:

area \: of \: shape \\  =  \frac{1}{2}  \times base \times height \\  \\  =  \frac{1}{2}  \times 10 \times 3 \\  \\  =  \frac{1}{2}  \times 30 \\  \\  = 15 \:  {yd}^{2}

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Mofor’s school is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 senior citizen t
kari74 [83]

Answer:

Senior citizen tickets = 9

Student tickets = 10

Step-by-step explanation:

We begin by converting the question into simultaneous linear equations;

Senior citizen tickets = a

Student tickets = b

4a + 6b = 96

8a + 13b = 202

to find a,

if 4a +6b = 96

a = 96/4 - 6b/4

a = 24 - 1.5b

We now substitute this into the second equation

8(24 - 1.5b) + 13b = 202

192 - 12b + 13b = 202

b = 202 - 192

b = 10

We now put the value of b in either equation

4a + 6b = 96

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4a + 60 = 96

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7 0
3 years ago
PLS HELP ME
IgorLugansk [536]

Answer :

Option B

Step by step explanation :

As we can see in figure, Triangle is right angled at A

In ∆ABC

By Pythagoras theorem,

BC² = AC² + AB²

=> BC² = (3)² + (4)²

=> BC² = 9 + 16

=> BC² = 25

=> BC = 5 cm

We know,

\:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2}\: x\: base\: x\: height}

Here,

base = AC = 3cm

height = AB = 4cm

=> \:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2} \:x\: 3cm\: x\:4cm}

=> \:\mathsf{Area \:of\: triangle\: = \:3cm\: x\: 2cm}

=> \:\bf\boxed{Area \:of\: triangle\: = \:6cm²}

As BC = DE

And then BD = EC

it shows the property of rectangle

So BD = 6 cm

Now,

\:\mathsf{Area \:of\: rectangle\: =\: length \:x\: width}

=> Area of rectangle = 6cm x 5cm

=> \:\bf\boxed{Area\: of\: rectangle\: = \:30cm²}

Now,

Area of the figure = Area of rectangle + Area of triangle

=> Area of the figure = 30cm² + 6cm²

=> \:\bf\boxed{Area\: of\: the\: figure\: = \:36cm²}

Therefore, <u>option B</u> is the correct answer for this question.

3 0
3 years ago
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