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3 years ago

90+90+(2x+4)+(3x-29)=360?

Mathematics

1 answer:

TiliK225 [7]3 years ago

8 0

What does "x" equal? You need to know that first to solve the problem

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Order the numbers from least to greatest -20 3/4 -14 3/4 -1/4 and -15 1/2

FinnZ [79.3K]

Answer:

-20 3/4, -15 1/2, -14 3/4,

Step-by-step explanation:

8 0

3 years ago

Which of the following phrases are inequalities?

suter [353]

Answer:

B, C D

Step-by-step explanation:

Inequalities are the "alligators" < or > or the "alligators" with lines ≤ or ≥

< less than

>greater than

≤ less than or equal to

≥ greater than or equal to

7 0

4 years ago

Read 2 more answers

ALGEBRA 2!!!!!!!!! SHOW YOUR WORK!!!!!!!!!!!!!<br> Do f(g(x)) and g(f(x))

bezimeni [28]

$\bf f(x)=\cfrac{2x-3}{x+1}~\hspace{10em}g(x)=\cfrac{x+3}{2-x}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
f(~~g(x)~~)\implies \cfrac{2[g(x)]-3}{[g(x)]+1}\implies \cfrac{2\left( \frac{x+3}{2-x} \right)-3}{\left( \frac{x+3}{2-x} \right)+1}\implies
\cfrac{\frac{2x+6}{2-x}-3}{\frac{x+3}{2-x}+1}
\\\\\\
\cfrac{\frac{2x+6-6+3x}{2-x}}{\frac{x+3+2-x}{2-x}}\implies \cfrac{2x+6-6+3x}{2-x}\cdot \cfrac{2-x}{x+3+2-x}\implies \cfrac{5x}{5}\implies x$

$\bf \rule{34em}{0.25pt}\\\\
g(~~f(x)~~)\implies \cfrac{[f(x)]+3}{2-[f(x)]}\implies \cfrac{\frac{2x-3}{x+1}+3}{2-\frac{2x-3}{x+1}}\implies \cfrac{\frac{2x-3+3x+3}{x+1}}{\frac{2x+2-(2x-3)}{x+1}}
\\\\\\
\cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-(2x-3)}\implies \cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-2x+3}
\\\\\\
\cfrac{5x}{5}\implies x$

and in case you recall your inverses, when f( g(x) ) = x, or g( f(x) ) = x, simply means, they're inverse of each other.

4 0

4 years ago

For an annual membership fee of $500, Mr.Bailey can join a country club that would allow him to play a round of golf for $35. Wi

mote1985 [20]

He would have to play 11 games. and 3 games plus a membership in order to equal the same amount of 605

6 0

3 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Dmitriy789 [7]

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18 true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18 false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4 True

7 0

3 years ago

Read 2 more answers