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3 years ago

What is 8 over 30 equal to?????

Mathematics

1 answer:

Mamont248 [21]3 years ago

8 0

$\dfrac{8}{30}=\dfrac{\not2\cdot4}{\not2\cdot15}=\dfrac{4}{15}$

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I need help with number 7 please help.

cestrela7 [59]

Y = 2x

Because for every serving there are 2 pints

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3 years ago

The decimal equivalent of 13/6 is a repeating decimal true or

zhannawk [14.2K]

Answer:

False

Step-by-step explanation:

13/6=2.16666667

6 0

3 years ago

Read 2 more answers

Which of the following expressions can be combined?

Rom4ik [11]

Answer: Choice C

Work Shown:

$2\sqrt{12} - 6\sqrt{27}\\\\2\sqrt{4*3} - 6\sqrt{9*3}\\\\2\sqrt{4}*\sqrt{3} - 6\sqrt{9}*\sqrt{3}\\\\2*2*\sqrt{3} - 6*3*\sqrt{3}\\\\4\sqrt{3} - 18\sqrt{3}\\\\(4-18)\sqrt{3}\\\\-14\sqrt{3}\\\\$

In short,

$2\sqrt{12} - 6\sqrt{27}=-14\sqrt{3}$

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2 years ago

Helpp!!! This is due Sunday. I don’t understand!

Darya [45]

Answer:

11, 15, 26, 41, could be an answer

6 0

4 years ago

Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com

fredd [130]

$f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}$

$f$ has critical points where the derivative is 0:

$2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1$

The second derivative is

$f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}$

and $f''(-1)=\frac2e>0$ , which indicates a local minimum at $x=-1$ with a value of $f(-1)=\frac1e$ .

At the endpoints of [-2, 2], we have $f(-2)=1$ and $f(2)=e^8$ , so that $f$ has an absolute minimum of $\frac1e$ and an absolute maximum of $e^8$ on [-2, 2].

So we have

$\dfrac1e\le f(x)\le e^8$

$\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx$

$\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}$

5 0

3 years ago