What is 8 over 30 equal to?????

the hundreds digit of my number is greater than the 10 digit. the one digit is less than the ten digit. what could my number be

muminat

<span>h > t, u < t can be written together either of these two ways:
u < t < h or h > t > u And it could be any of these 120 numbers:
210 310 320 321 410 420 421 430 431 432 510 520 521 530 531 532 540 541 542 543 610 620 621 630 631 632 640 641 642 643 650 651 652 653 654 710 720 721 730 731 732 740 741 742 743 750 751 752 753 754 760 761 762 763 764 765 810 820 821 830 831 832 840 841 842 843 850 851 852 853 854 860 861 862 863 864 865 870 871 872 873 874 875 876 910 920 921 930 931 932 940 941 942 943 950 951 952 953 954 960 961 962 963 964 965 970 971 972 973 974 975 976 980 981 982 983 984 985 986 987
</span>

6 0

2 years ago

Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

3/4 (x - 3) - 5 = 1/8 ( x - 1 )

KonstantinChe [14]

Answer:

x = - $\frac{57}{5}$

Step-by-step explanation:

$\frac{3}{4}$ (x - 3) - 5 = $\frac{1}{8}$ (x - 1)

Multiply through by 8 to clear the fractions

6(x - 3) - 40 = x - 1 ← distribute parenthesis and simplify left side

6x - 18 - 40 = x - 1

6x - 58 = x - 1 ( subtract x from both sides )

5x - 58 = - 1 ( add 58 to both sides )

5x = - 57 ( divide both sides by 5 )

x = - $\frac{57}{5}$

3 0

2 years ago

Suppose you are driving 60 miles per hour. what is your rate of speed in miles per minute?

Verdich [7]

So if it is 60 miles per hour it is basically 60 miles per 60 minutes. $\frac{60}{60}$ when you simplify it, it is going to be 1/1=1 The answer is 1 mile per minute

6 0

2 years ago

Read 2 more answers

A storage box has a length of 4 inches, width of 4 inches and height of 3 1/2inches. What is the volume of the box?

ArbitrLikvidat [17]

V=LxWxH
4x4x3 1/2 = 56

7 0

2 years ago