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2 years ago

If a vertical angle has 74 degree and also opposite angle is 2x degree ,what is value of x?

Mathematics

1 answer:

UNO [17]2 years ago

6 0

Answer:

x = 37

Step-by-step explanation:

Well if you didn't know vertical angles are congruent ( or equal to each other )

Which means that 74 = 2x

If we want to find the value of x, then we need to get rid of the "2" on 2x

To do so we can divide each side by 2

74 / 2 = 37

2x / 2 = x

we would be left with x = 37

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3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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3 years ago

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Step-by-step explanation:

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3 years ago

If a vertical angle has 74 degree and also opposite angle is 2x degree ,what is value of x?​

If a vertical angle has 74 degree and also opposite angle is 2x degree ,what is value of x?