Which line is the best fit line for the given data?

Determine which relation is a function. Question 13 options: a) {(3, 0), (– 2, – 2), (7, – 2), (– 2, 0)} b) c) y = 15x + 2 y = 1

antiseptic1488 [7]

Answer:

x=3−2d,5,−2(1+d),5,−27−2d,5,−2(2+d),5,2(y−d),5

Step-by-step explanation:Solving for x. Want to solve for y or solve for d instead?

1 Simplify 0-20−2 to -2−2.

3,-2,-27,-2-2,02y=1,5x+2d3,−2,−27,−2−2,02y=1,5x+2d

2 Simplify -2-2−2−2 to -4−4.

3,-2,-27,-4,02y=1,5x+2d3,−2,−27,−4,02y=1,5x+2d

3 Subtract 2d2d from both sides.

3-2d,-2-2d,-27-2d,-4-2d,02y-2d=1,5x3−2d,−2−2d,−27−2d,−4−2d,02y−2d=1,5x

4 Divide both sides by 1,51,5.

\frac{3-2d}{1},5,\frac{-2-2d}{1},5,\frac{-27-2d}{1},5,\frac{-4-2d}{1},5,\frac{02y-2d}{1},5=x

1

3−2d

 ,5,

1

−2−2d

 ,5,

1

−27−2d

 ,5,

1

−4−2d

 ,5,

1

02y−2d

 ,5=x

5 Factor out the common term 22.

\frac{3-2d}{1},5,\frac{-2(1+d)}{1},5,\frac{-27-2d}{1},5,\frac{-4-2d}{1},5,\frac{02y-2d}{1},5=x

1

3−2d

 ,5,

1

−2(1+d)

 ,5,

1

−27−2d

 ,5,

1

−4−2d

 ,5,

1

02y−2d

 ,5=x

6 Factor out the common term 22.

\frac{3-2d}{1},5,\frac{-2(1+d)}{1},5,\frac{-27-2d}{1},5,\frac{-2(2+d)}{1},5,\frac{02y-2d}{1},5=x

1

3−2d

 ,5,

1

−2(1+d)

 ,5,

1

−27−2d

 ,5,

1

−2(2+d)

 ,5,

1

02y−2d

 ,5=x

7 Factor out the common term 22.

\frac{3-2d}{1},5,\frac{-2(1+d)}{1},5,\frac{-27-2d}{1},5,\frac{-2(2+d)}{1},5,\frac{2(y-d)}{1},5=x

1

3−2d

 ,5,

1

−2(1+d)

 ,5,

1

−27−2d

 ,5,

1

−2(2+d)

 ,5,

1

2(y−d)

 ,5=x

8 Simplify \frac{3-2d}{1}

1

3−2d

 to (3-2d)(3−2d).

3-2d,5,\frac{-2(1+d)}{1},5,\frac{-27-2d}{1},5,\frac{-2(2+d)}{1},5,\frac{2(y-d)}{1},5=x3−2d,5,

1

−2(1+d)

 ,5,

1

−27−2d

 ,5,

1

−2(2+d)

 ,5,

1

2(y−d)

 ,5=x

9 Simplify \frac{-2(1+d)}{1}

1

−2(1+d)

 to (-2(1+d))(−2(1+d)).

3-2d,5,-2(1+d),5,\frac{-27-2d}{1},5,\frac{-2(2+d)}{1},5,\frac{2(y-d)}{1},5=x3−2d,5,−2(1+d),5,

1

−27−2d

 ,5,

1

−2(2+d)

 ,5,

1

2(y−d)

 ,5=x

10 Simplify \frac{-27-2d}{1}

1

−27−2d

 to (-27-2d)(−27−2d).

3-2d,5,-2(1+d),5,-27-2d,5,\frac{-2(2+d)}{1},5,\frac{2(y-d)}{1},5=x3−2d,5,−2(1+d),5,−27−2d,5,

1

−2(2+d)

 ,5,

1

2(y−d)

 ,5=x

11 Simplify \frac{-2(2+d)}{1}

1

−2(2+d)

 to (-2(2+d))(−2(2+d)).

3-2d,5,-2(1+d),5,-27-2d,5,-2(2+d),5,\frac{2(y-d)}{1},5=x3−2d,5,−2(1+d),5,−27−2d,5,−2(2+d),5,

1

2(y−d)

 ,5=x

12 Simplify \frac{2(y-d)}{1}

1

2(y−d)

 to (2(y-d))(2(y−d)).

3-2d,5,-2(1+d),5,-27-2d,5,-2(2+d),5,2(y-d),5=x3−2d,5,−2(1+d),5,−27−2d,5,−2(2+d),5,2(y−d),5=x

13 Switch sides.

x=3-2d,5,-2(1+d),5,-27-2d,5,-2(2+d),5,2(y-d),5x=3−2d,5,−2(1+d),5,−27−2d,5,−2(2+d),5,2(y−d),5

Done

5 0

2 years ago

Ben said the graph of the inequality

Ksivusya [100]

Answer:

Ben is incorrect

The solutions are x>-3 and x < 3

Step-by-step explanation:

we have

$-x^{2} +9 > 0$

Multiply by -1 both sides

$x^{2} -9 < 0$

Adds 9 both sides

$x^{2} < 9$

The solutions are

$x < 3$

and

$-x < 3$ -----> Multiply by -1 both sides ----> $x > -3$

therefore

The solution is the interval (-3,3)

Ben is incorrect

7 0

2 years ago

Jon bought a printer for $189 and a set of printer cartridges for $192. Sales tax on these items was 6.5%. What is Jon's total b

julia-pushkina [17]

So first we need to find the total before tax. Let's add up the two prices:

$189+192=381$

So we know that the total before tax is $381. Now we are told that the sales tax on these items is 6.5%. It would be easier for us to convert 6.5% to a decimal in order to multiply. Let's convert 6.5% to a decimal by dividing by 100:

$\frac{6.5}{100}=0.065$

Now that we have the sales tax in decimal form, let's multiply this sales tax by the total amount of the items before tax ($381):

$381*0.065=24.77$

This means that $24.77 is the tax for this purchase. To find the total amount that Jon paid for these items after tax, you must add the tax to the total amount before tax to give you:

$381+24.77=405.77$

So now we know that Jon's total bill for these items is $405.77.

4 0

2 years ago

Can someone solve this for me with their explanation please?

Lana71 [14]

First you want to subtract 36

so it looks like this $\sqrt[4] {(4x+164)^3}=64$