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brilliants [131]
3 years ago
10

A holiday store is having a sale on bows and rolls of wrapping paper. One sign in the store states, “Buy 1 bow and 1 roll of wra

pping paper for only $6.00.” A second sign in the store states, “5 bows and 1 roll of wrapping paper will only cost $10.00.”
In dollars and cents, the cost of a single roll of wrapping paper costs $
.
Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

3.00

Step-by-step explanation:

One bow and and 1 roll of wrapping paper  cost 6.00$

so the roll by itself would cost 6.00$

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Timothy is filling fish bowls with pebbles at his fish store. He wants to have $\frac{1}{6}$ of a pound of pebbles in each fish
Luba_88 [7]

Answer:

14

Step-by-step explanation:

Given that:

Each fish bowl to have pebbles of weight equivalent to = \frac{1}{6}

Total pounds of pebbles that Timothy can use = 2\frac{1}{3}

To find:

The greatest value of Total number of fish bowls that Timothy can fill ?

Solution:

First of all, we need to convert mixed fraction into a fractional number and then we also need to see division of two fractions.

Formula:

1. \ p\dfrac{q}{r} = \dfrac{p\times r+q}{r}\\2. \ \dfrac{\frac{a}{b}}{\frac{c}d}=\dfrac{a\times d}{b\times c}

Now, the given mixed fraction can be converted to fractional number as:

2\dfrac{1}{3} = \dfrac{2\times 3+1}{3} = \dfrac{7}{3}

Now, To find the total number of fish bowls that can be filled, we need to divide the total number of pounds with number of pounds of pebbles in each fish bowl.

So, the answer is:

\dfrac{\frac{7}{3}}{\frac{1}{6}}\\\Rightarrow \dfrac{7\times 6}{3\times 1}\\\Rightarrow \dfrac{42}{3}\\\Rightarrow \bold{14}

<em>14</em> number of fish bowls can be filled.

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3 years ago
Let X represent the number of children in a Canadian household. The probability distribution of X is: x 1 2 3 4 p(x) 0.30 0.35 0
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Answer:0.45

Step-by-step explanation:

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50 out of 100 flowers are red. What percentage of the flowers are red
GuDViN [60]

Answer:

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Step-by-step explanation:

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