116.15 round to nearest 10th

In a group of equal number of men and women 10% men and 45% women are suffering from Malaria.What is probability a peraon select

Kaylis [27]

Answer:

The probability a person selected random is not suffering from Malaria is 0.725.

Step-by-step explanation:

Denote the events as follows:

X = a person is suffering from Malaria

M = a man

W = a woman

The information provided is:

P (M) = P (W) = 0.50

P (X|M) = 0.10

P (X|W) = 0.45

Compute the probability a person selected random is suffering from Malaria as follows:

$P(X)=P(X|M)P(M)+P(X|W)P(W)$

$=(0.10\times 0.50)+(0.45\times 0.50)\\\\=0.05+0.225\\\\=0.275$

Then the probability a person selected random is not suffering from Malaria is:

P (X') = 1 - P (X)

= 1 - 0.275

= 0.725

4 0

3 years ago

PLEASE ANSWER ILL GIVE YOU BRIANLIEST

GREYUIT [131]

Answer:

I Think It's 523.6 I don't know Tho

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the value of 5x+ 3 when X= 4? 9 12 23 60

Bingel [31]

The answer is 23 because you would substitute in the 4 for the X and multiply 5 times 4 = 20 then add 20 plus 3 and you get 23

7 0

3 years ago

Read 2 more answers

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$

And the standard deviation of the distribution of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74$

Thus, the distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b)

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

*Use a z-table for the probability.

Thus, the value of $P(\bar X$ is 0.7642.

(c)

Compute the value of $P(\bar X\geq 69.1)$ as follows:

Apply continuity correction as follows:

$P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)$

$=P(\bar X>69.6)$

$=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})$

$=P(Z>0.34)\\=1-P(Z$

Thus, the value of $P(\bar X\geq 69.1)$ is 0.3670.

7 0

3 years ago

Owen is fishing from a dock he starts with the bait 2 feet below the surface he reels out the boat 19 feet then reels it back in

Hatshy [7]

Answer:

The bait is 14 feet below the water surface

Step-by-step explanation:

Here, we want to know the final position of the bait relative to the surface of the water.

Firstly, he starts with the bait at 2 feet below the water surface. The reels out the bait a further 19 feet, the new position of the bait relative to the water surface will be 2 + 19 = 21 feet

Now, he reels the bait back by 7 feet.

Thus, the new depth of the bait relative to the water surface will be 21-7 = 14 feet

4 0

3 years ago