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4 years ago

The length of the side opposite B measures __ units

Mathematics

2 answers:

Sindrei [870]4 years ago

7 0

For this case what we should do is observe the figure.

We note that the side opposite to vertex B is the AC side.

From here, we can see that the length of the AC segment is given by:

AC = 4

Therefore, the measurement on the side opposite to vertex B is equal to 4 units.

Answer:

The length of the side opposite B measures 4 units

eimsori [14]4 years ago

7 0

Answer:

4 units

Step-by-step explanation:

From the figure, it is given that ABC is a triangle and AB=5, BC=3 and AC=4.

Now, In order to get the length of the side opposite B, it can be determined by simply seeing the side opposite to the angle B.

From the given figure, it can be seen that AC is the side opposite to the angle B and is equal to 4, thus the length of the side opposite B measures 4 units.

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3 years ago

Read 2 more answers

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natka813 [3]

Answer:

(a) 8 balls

(b) 4 balls

Step-by-step explanation:

Let

$N \to$ Number of balls

For a box, the probability that there are N balls in it is:

$Pr = 0.5^N$

For 2 boxes, it is:

$Pr = 2 * 0.5^N$

From the question, we have:

$\frac{80}{10000} \to$ Favorable outcome

To solve for N, we have:

$2 * 0.5^N = \frac{80}{10000}$

$2 * 0.5^N = 0.008$

Divide both sides by 2

$0.5^N = 0.004$

Take log of both sides

$\log(0.5^N) = \log(0.004)$

Apply law of logarithm

$N\log(0.5) = \log(0.004)$

Make N the subject

$N = \frac{\log(0.004)}{\log(0.5)}$

$N =7.966$

Approximate

$N = 8$

Solving (b): Balls in one of the two boxes.

Here, we assume that each ball will have almost the same number of balls at a given instance;

Hence, we have:

$Balls \approx \frac{N}{2}$

$Balls \approx \frac{8}{2}$

$Balls \approx 4$

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3 years ago

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Answer:

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Step-by-step explanation:

a^-1 = 1/a

So here we have:

(8/5)^-1

= 1/ (8/5)= 5/8.

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3 years ago

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