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lukranit [14]
3 years ago
6

What is the measure of ENV

Mathematics
2 answers:
Anit [1.1K]3 years ago
4 0
50 is the correct answer. Hope this helps
Rainbow [258]3 years ago
4 0

Answer:

Step-by-step explanation:

Tinker what’s yo snap

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Given: P is a point on the perpendicular bisector, I of MN.<br> Prove: PM = PN
Hatshy [7]

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN                Parts contained in Congruent triangles are congruent.

5 0
3 years ago
Solve the system algebraically. Check your work. 5x + 2y = 10 3x + 2y = 6 Make sure there are NO SPACES in your answer. Be sure
e-lub [12.9K]
For the first equation its y=5-2/5x or y=-2/5x+5
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3 years ago
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Whoever gets this right, gets cake
Mariana [72]

Answer:

D is the answer

Step-by-step explanation:

don't froget my cake!! :)

5 0
2 years ago
Find the volume of a cylinder with a diameter if 10 cm and a height of 10 cm?​
RideAnS [48]

Step-by-step explanation:

volume of cylinder=π(d/2)²h=π/4×10²×10=250πcm³

7 0
2 years ago
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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

n = 1537, \pi = \frac{353}{1537} = 0.2297

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0
3 years ago
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