Answer:
I am not sure but I think that it is the second set?
Step-by-step explanation:
108
Step-by-step explanation:
because you would have to take the width times the height and that is 52 times 4
Step-by-step explanation:
<u>Properties used</u>
- logₐ a = 1
- log aᵇ = b log a
- log ab = log a + log b
See the steps below
- - log (4*10⁻³) =
- - (log 4 + log 10⁻³) = (log 4 ≈ 0.6 rounded)
- - (0.6 - 3*log 10) =
- - (0.6 - 3*1) =
- - (0.6 - 3) =
- - (- 2.4) =
- 2.4
1) split the range in three identical invervals of size [6 - 0] / 3 = 2
2) form three rectangles
2a) First rectangle: base 2, height f(2) = 2^2 + 1 = 5
area 1 = base * height = 2 * 5 = 10
2b) second rectangle: base 2, height f(2+2) = 4^2 + 1 = 17
area 2 = 2 * 17 = 34
2c) third rectangle: base 2 height f(4+2) = 6^2 + 1 = 37
area 3 = 2*37 = 74
3) total area = area 1 + area 2 + area 3 = 10 + 34 + 74 = 118
Step-by-step explanation:
- in order to know if the the point is on the line plug in the x coordinate to check if it gives you the y coordinate as an output.
- If you plug in the x coordinate and it gives you the given y coordinate then the point is on the given line
- Now let us plug in the value of x=-3
- now if you check plugging in the given x coordinate it does not give you the given y coordinate but -2
- therefore the point(-3,7) is not in the line but (-3,-2) is the point in the line.
