Answer:
BD = 35
Step-by-step explanation:
Calculate CD in right triangle ABC, then BD in right triangle BCD
Using Pythagoras' identity in both triangles.
The square on the hypotenuse is equal to the sum of the squares on the other two sides.
In Δ ADC
CD² + AD² = AC² , substitute values
CD² + 9² = 15²
CD² + 81 = 225 ( subtract 81 from both sides )
CD = 144 ( take the square root of both sides )
CD = 
= 12
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In Δ BCD
BD² + CD² = BC² , substitute values
BD² + 12² = 37²
BD² + 144 = 1369 ( subtract 144 from both sides )
BD² = 1225 ( take the square root of both sides )
BD = 
= 35
Answer & Step-by-step explanation:
In the problem, we are given an equation. h(t) = -20 + 11t
In the equation, t represents an unknown value. So, if we are given a number that is in the replacement of t, then we can plug that number in to where t is at.
t = 11
h(11) = -20 + 11(11)
h(11) = -20 + 121
h(11) = 101
So, h(11) is equal to 101
Good evening
Answer:
<h2>measure of Angle 1 = 81°</h2><h2>Measure of angle 2 = 9°</h2>
Step-by-step explanation:
we need to solve this system
x + y = 90 (1)
x = y + 72 (2)
If we substitute x by y+72 into the equation (1) we will get
(y+72) + y = 90 ⇔ 2y + 72 = 90 ⇔ 2y = 90 - 72 = 18 ⇔ y = 9
then x = 90 - 9 = 81
:)
No cuz if a number is dividable by 2 then it's even if the number is not even then it is not dividable by 2.
Answer:
347.037461955
Step-by-step explanation:
If you are taking the square root of 120,435. I would just put it into a calculator.
