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Ivanshal [37]
3 years ago
11

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

rk with a 52 foot chord and a middle ornate of 6 feet. What is the minimum speed she could have been going?
Mathematics
1 answer:
Aneli [31]3 years ago
8 0
First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: r= \frac{c^2}{8m} + \frac{m}{2}
where 
c is the length of the chord 
m is the middle ordinate 
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so c=52 and m=6. Lets replace those values in our formula:
r= \frac{52^2}{8(6)} + \frac{6}{2}
r= \frac{2704}{48} +3
r= \frac{169}{3} +3
r= \frac{178}{3}

Next, to find the minimum speed, we are going to use the formula: s= \sqrt{15fr}
where
f is <span>drag factor
</span>r is the radius 
We know form our problem that the drag factor is 0.2, so f=0.2. We also know from our previous calculation that the radius is \frac{178}{3}, so r= \frac{178}{3}. Lets replace those values in our formula:
s= \sqrt{(15)(0.2)( \frac{178}{3}) }
s= \sqrt{178}
s=13.34 mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour. 
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