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Tems11 [23]
3 years ago
9

Janie receives an allowance of \$3$3dollar sign, 3 per week. In addition, she can earn \$2$2dollar sign, 2 for each chore she do

es. This week, she wants to earn enough money to buy a CD for \$13$13dollar sign, 13. Janie can do fractions of chores.
Write an inequality to determine the number of chores, ccc, Janie must do this week to earn enough money to buy a CD.

3+2(c)=13
Identify which graph represents the solution set to this inequality.

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

The first thing we must do for this case is to define variables.

We have then:

c: number of chores that Janie sells

We write now the inequality that models the problem.

We have then:

2c + 3\geq 13

The solution of the inequality are all those points that belong to the numerical line shown. (See attached image)

Answer:

2c + 3 \geq 13

See attached image

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Hitman42 [59]

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2 years ago
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aksik [14]

Answer:

Step-by-step explanation:

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2. There are two values on the spinner that are a multiple of 3, 3 itself and 6. Again, the total amount of numbers/sections is 8, so the probability of spinning a multiple of three is 2/8 or 1/4. The probability of spinning an odd number is 4/8 or 1/2. (1/2)*(1/4)=1/8 is the probability.

3. The probability of spinning one odd number is 1/2, and so we multiply 1/2 by itself four times. (1/2)*(1/2)*(1/2)*(1/2)=1/16 is the probability.

4. There are 6 numbers greater than two on the number wheel not including two itself. So the probability of that is 6/8, or 3/4. Then we multiply 3/4 by itself 3 times as it asks. (3/4)*(3/4)*(3/4)*(3/4)=81/256 is the probability.

Note that I am not really sure about the answer myself, but I hope that this can help in some way. Good luck! :)

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3 years ago
Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other.
erastovalidia [21]

The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.

<h3>What are the proves?</h3>

1.  To know  collinear vectors:

∧ ⁻a ║ ⁻a

If  ⁻b = ∧ ⁻a

then |⁻b| = |∧ ⁻a|

So one can say that  line ⁻b and ⁻a are  collinear.

2.  If ⁻a and ⁻b  are collinear

Assuming |b| length  is  'μ' times of |⁻a |

Then | 'μ' ⁻a| = | 'μ' ⁻a|

So  ⁻b = 'μ' ⁻a

Learn more about vectors  from

brainly.com/question/25705666

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