Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
Answer:
Second point (-5/2, -7/2)
First point (3/2, 17/2)
Step-by-step explanation:
We have two equations, and we want to know at wich poin are equal. Hence, we have a system of equations and the solution is nothing more that the point (x,y) where those functions intercepts.
4x2+ 7x -11=y
3x+4=y
Lets use substitute method
4x2+7x-11=3x+4
This can be re arrange as the following eq:
4x2+4x-15=0
A quadratic equation, its solution can be obtained using the below eq.

where a=4, b=4, c=-15.
Remember, the quadratic equation as a +/- sign, meaning that you will obtain one answer using the + operator and other using the - operator.
By doing the above, we have x=-5/2 and x=3/2
By using x=3/2 in equation of line (3x+4=y) we have y=17/2
First point (3/2, 17/2)
By using x=-5/2 in equation of line (3x+4=y) we have y= -7/2
Second point (-5/2, -7/2)
Those points are the ones where the line and the parabola intercept.
Answer:
area of sector BCD =60/360×π×10²=52.36ft²
a area of sector ADC =90/360×π×√50²=39.27ft²
actual <u>area</u><u> </u><u>=</u><u>5</u><u>2</u><u>.</u><u>3</u><u>6</u><u>ft²-39</u><u>.</u><u>2</u><u>7</u><u>f</u><u>t</u><u>²</u><u>=</u><u>1</u><u>3</u><u>.</u><u>0</u><u>9</u><u>=</u><u>1</u><u>3</u><u>ft²</u>
Answer:
nope
Step-by-step explanation:
n-o-p-e