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3 years ago

Slope and point on line of the equation y - 6= 3(x-5)

Mathematics

1 answer:

lakkis [162]3 years ago

6 0

Easy claps

Answer: slope=3 and point is (5,6)

Step-by-step explanation: It's just basic prealgebra!

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A seamstress needs to cut 15- inches pices of ribbons from a roll of ribbon that is 9 feet in length. What is the greatest numbe

sertanlavr [38]

The seamstress can cut 36, 15-inch pieces of ribbon from 5 rolls of 9 foot long ribbon.

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3 years ago

Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at $(x_1,y_1)$ and point Q at $(x_2,y_2)$ in the proportion a:b, we use the formula:

$x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1$

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

$x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1$

4 0

3 years ago

Can someone please do this for me?

san4es73 [151]

Answer:

64°

Step-by-step explanation:

So supplement angles are equal to 180, so first our two angles added together will be 180:

x + x = 180

Now one of these angles is 6 greater than half:

x + (x/2 + 6) = 180

Then we will solve for x:

x + (x/2 + 6) = 180

x + x/2 + 6 = 180

x + x/2 = 174

$\frac{3}{2}$ x = 174

x = 116

Plug it back in:

x + (x/2 + 6) = 180

x/2 + 6

(116)/2 + 6

To check:

116 + 64 = 180 ✓

6 0

3 years ago

Can u guys help wit a little bit more questions what is 9.04-6.98

Goryan [66]

Answer:

9.04-6.98=2.06

4 0

2 years ago

Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w

Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

$\vec {v}=\left$

Now, the perimetric equations for initial point $(x_0,y_0,z_0)$ with direction vector $\vec{v}=\left$ , are

$x=x_0+at$

$y=y_0+bt$

$z=z_0+ct$

The initial point is (7,1,-5) and direction vector is $\vec {v}=\left$ . So the perimetric equations are

$x=(7)+(-4)t$

$x=7-4t$

Similarly,

$y=1+3t$

$z=-5+3t$

Therefore, the required perimetric equations are $x=7-4t, y=1+3t$ and $z=-5+3t$ .

5 0

3 years ago