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3 years ago

Please help me I need this ASAP

Mathematics

1 answer:

docker41 [41]3 years ago

4 0

Answer:

Option A is correct.

Step-by-step explanation:

We have been given that the there are 6 medals which are to be awarded from first place through 6th place

So, there will be arrangement of the medals among 6 medals so, it will be 6!

$6!=6\cdot 5\cdot 4\cdot3\cdot 2\cdot 1=720$

Therefore, Option A is correct that is permutation; number of ways 720.

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What is the x-intercept for the following linear equation:

Alexandra [31]

The "x-intercept" occurs when y=0, because it is at this point that the equation touches the x axis. So if you plug in y=0 into the equation you can solve for the x coordinate.

4x-2(0)-8=0

4x-8=0

4x=8

x=2

So the x-intercept is the point (2,0)

3 0

3 years ago

Q2 (i). A line “t” is parallel to 3y = 6x + 9. Find the slope of this line “t”. (ii) Another line “r” is perpendicular to the li

Mariulka [41]

Answer: 6 and -1/6

Step-by-step explanation:

solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.

7 0

3 years ago

Read 2 more answers

Which of the following are integers? 13 14 -16 147 1000000 -3 -0.35

nikklg [1K]

Answer:

13 integer

14 integer

-16 integer

147 integer

100000 integer

-3 integer

-0.35 not integer

Explanation:

The integers are all negative or positive whole numbers

7 0

2 years ago

Read 2 more answers

What is the equation of the line that passes through the points (−2, 1) and (1, 10)? 3x − y = −73x − y = −53x − y = 5x + 3y = −5

djyliett [7]

The two point formula :

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The points are (-2, 1) and (1, 10)

Using the formula above :

$\begin{gathered} y-1=\frac{10-1}{1-(-2)}(x+2) \\ y-1=\frac{9}{3}(x+2) \\ y-1=3(x+2) \\ y-1=3x+6 \\ -3x+y=6+1 \\ -3x+y=7 \\ 3x-y=-7 \end{gathered}$

The answer is 3x - y = -7

7 0

1 year ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

Step-by-step explanation:

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

Step-by-step explanation:

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$

Area of ΔBEF:

$\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18$

5 0

3 years ago