Ask question

Ask question

All categories

3 years ago

15

Write a 10 digit number such that the first digit tells how many zeros there are in the entire number, the second digit tells ho

w many ones there are in the numeral, the third digit tells how many twos there are, and so on.

1 answer:

Dmitry [639]3 years ago

4 0

6210001000
6 0s
2 1s
1 2s
0 3s
04s
05s
1 6s
0 7s
0 8s
0 9s

You might be interested in

Suppose a mutual fund qualifies as having moderate risk if the standard deviation of its monthly rate of return is less than 5%

Leokris [45]

Answer:

$\chi^2 =\frac{28-1}{25} 21.7156 =23.453$

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(23.453,27,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly lower than 5% so we can't conclude that we have a moderate risk for this case.

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=28$ represent the sample size

$\alpha=0.1$ represent the confidence level

$s^2 =21.7156$ represent the sample variance obtained

$\sigma^2_0 =25$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 25, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{28-1}{25} 21.7156 =23.453$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 27. And since is a right tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(23.453,27,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly lower than 5% so we can't conclude that we have a moderate risk for this case.

4 0

3 years ago

What number belongs in the blank space below

Setler79 [48]

The number that belongs in the blank space is answer choice A. 6

6 0

3 years ago

Olivia is thinking of a number.She says, "My number is odd. It is a factor of 30 and a multiple of 3"

Katarina [22]

Answer:

15

Step-by-step explanation:

Factors of 30:

1 , 2, 3, 5, 6, 10, 15, 30

Multiples of 3:

3, 6, 9, 12, 15, etc.

The first number (and only number) shared by both sets is 15, therefore 15 is your answer.

~

8 0

3 years ago

Read 2 more answers

How do you solve this? Need help please

nirvana33 [79]

Answer:

2x^2/3yz^7

Step-by-step explanation:

6 0

3 years ago

In a reliability test there is a 42% probability that a computer chip survives more than 500 temperature cycles. If a computer c

Strike441 [17]

Answer:

The probability is $P(B' n A ' ) =$ 16%

Step-by-step explanation:

From the question we are told that

A is the event that the chip was "made by company A"

B is the event that a chip "survives 500 temperature cycles"

The probability that a computer chip survives more than 500 temperature cycles is

$P(B) = 42$ % $= 0.42$

The probability that does not survive more than 500 temperature cycles and it was manufactured by company A is $P(A | B' ) = 0.73$

The probability that the computer chip is not manufactured by company A and does not survive more than 500 temperature cycles is mathematically evaluated as

$P(B' n A ' ) = P (B' | A' ) P(B ')$

Where $B' \ and \ A'$ are a A and B complements and | represented AND operator

So

$P(B' n A ' ) = [1 - P (B' | A )] [1 - P(B )]$

substituting values

$P(B' n A ' ) = [1 - 0.73] [1 - 0.42 ]$

$P(B' n A ' ) = (0.27 )(0.58)$

$P(B' n A ' ) =0.16$

$P(B' n A ' ) =$ 16%

7 0

3 years ago