The vertex of this parabola is at (-3, 2). Which of the equations below could be its equation?

kodGreya [7K]

Yes, it’s D because you would have want to compare both fractions by making them have the same denominator. Since 60 is the least common denominator for 10 and 12 (the denominators), you would convert the fractions by multiplying the numerator and denominator of 5/10 by 6 to get 60. 5/10 would turn into 30/60. Then you would multiply 6/12 both by 5, and then it would turn into 30/60. Now that you have equal fractions, you can guess that they are the same. Therefore, 30/60=30/60! An easier way of doing it would be just simplifying them into 1/2 and comparing them + seeing that they are both 1/2. Hope this helps!

•••

Caramelatte

7 0

2 years ago

Given C=n+15, determine the value of C when n=4

puteri [66]

Answer: c=19 and n=4

please mark as brainliest if it helped

6 0

2 years ago

Read 2 more answers

A family prepares an emergency kit for their home. The kit contains 63 gallons of drinking water. The family's daily drinking w

mr_godi [17]

Answer:

12 days

Step-by-step explanation:

Total gallons of the family's drinking water needs = gallons consumed by children + gallons consumed by adults

3 $\frac{1}{2}$ + 1 $\frac{3}{4}$ =

Converting to decimals

3.5 + 1.75 = 5.25 = 5 $\frac{1}{4}$

If there are 63 gallons, the water supply would last for :

63 / 5.25 =12 days

6 0

2 years ago

Katrina is asked to simplify the expression Negative 3 a minus 4 b minus 2 (5 a minus 7 b).

lara31 [8.8K]

Answer:

oofyios

Step-by-step explanation:

5 0

2 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago