Answer:
Part a) The inequality that represent the situation is
Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to 
Step-by-step explanation:
Let
x------> the length of the first wire
3x---> the length of the second wire
2(3x)=6x -----> the length of the third wire
Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION
we know that
The inequality that represent the situation is
Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?
we know that
The shortest piece of wire is the first wire
so
Solve the inequality
Divide by 10 both sides
The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
Answer: the answer is 8 because
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Option B is the answer
Answer:
The class with the greatest is 138- 202 and the class with the least relative frequency is 333 - 397
Step-by-step explanation:
Solving (a): The frequency distribution
Given that:
--- i.e. the lowest class value
--- Number of classes
From the given dataset is:
So, the range is:
Divide by the number of class (5) to get the class width
Approximate
So, we have a class width of 64 in each class;
The frequency table is as follows:
Solving (b) The relative frequency histogram
First, we calculate the relative frequency by dividing the frequency of each class by the total frequency
So, we have:
See attachment for histogram
The class with the greatest is 138- 202 and the class with the least relative frequency is 333 - 397
